Tag: evaluate expressions

#include<stdio.h>
int main()
{
    int a, b, c, d, e, f, g, h, k;
    a = 8, b = 4, c = 2, d = 1, e = 5, f = 20;
    printf("%d\t", a + b - (c + d) * 3 % e + f / 9);
    a = 17, b = 5, c = 6, d = 3, e = 5;
    printf("%d\t", a % 6 - b / 2 + (c * d - 5) / e);
    a = 4, b = 5, c = 6, d = 3, e = 5, f = 10;
    printf("%d\t", a * b - c / d < e + f);
    a = 8, b = 5, c = 8, d = 3, e = 65, f = 10, g = 2, h = 5, k = 2;
    printf("%d\t", a - b + c / d == e / f - g + h % k);
    a = 8, b = 3, c = 2, d = 3, e = 2, f = 11;
    printf("%d\n", a - b || (a - b * c) + d && e - f % 3);
    return 0;
}